**Function overloading:**

In c++ two or more
function having the same name but the different parameter is called function
overloading.

To
see why function overloading is important, first consider three functions
defined by the c subset:

**abs(), labs(),**and**fabs()**. The**abs()**functions returns the absolute value of an integer,**labs()**returns the absolute value of long, and**fabs()**returns the absolute value of double.**Ex:**

#include <iostream>using namespace std;// abs is overloaded three waysint abs(int i);double abs(double d);long abs(long l);int main(){cout << abs(-10) << "\n";cout << abs(-11.0) << "\n";cout << abs(-9L) << "\n";return 0;}int abs(int i){cout << "Using integer abs()\n";return i<0 ? -i : i;}double abs(double d){cout << "Using double abs()\n";return d<0.0 ? -d : d;}long abs(long l){cout << "Using long abs()\n";return l<0 ? -l : l;

}

**Output:**

Using integer abs()

10

using double abs()

11

using long abs()

9

Here an overloaded function is

**abs.**as you can see, at the above program function name**abs**are the same for three functions, but the parameter type(int, long, double) differs.
In
General, overload a function, simply declare the different version of it. You must
observe one important restriction when overloading a function that is, the
number of the parameters of each overloaded function must differ.

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